South Africa defeated Zimbabwe by five wickets on Sunday in the Super Eight Group One of the Twenty20 World Cup 2026.
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South Africa defeated Zimbabwe by five wickets in the Super Eight Group One of the Twenty20 World Cup 2026 on Sunday. Chasing 154 runs for victory, South Africa achieved the winning target in 17.5 overs for the loss of five wickets. With this, South Africa became the only unbeaten team in the tournament. South Africa had already reached the semi-finals.
Dewald Brewis top-scored with 42 runs off 18 balls. Similarly, Ryan Rickelton added 31 runs off 22 balls. George Linde scored 30 and Tristan Stubbs remained unbeaten on 21 runs. For Zimbabwe, captain Sikandar Raja took three wickets for 29 runs. Zimbabwe, who decided to bat first after winning the toss, scored 153 runs for the loss of seven wickets.
Captain Raja top-scored with 73 runs. He hit eight fours and four sixes off 43 balls. Similarly, Clive Manande scored 26 runs off 20 balls. South African bowlers Kewena Mafka and Corbin Boach took two wickets each. Zimbabwe's chances of reaching the semi-finals had already ended. Zimbabwe lost all three of their matches in the Super Eights.
